Learn about nucleic acids with interactive visualizations. Explore DNA and RNA structure, function, replication, transcription, and translation with step-by-step animations and examples.
Nucleic acids are macromolecules that store and transmit genetic information in all living organisms. The two main types are DNA (deoxyribonucleic acid) and RNA (ribonucleic acid). These molecules are composed of nucleotides linked together by phosphodiester bonds.
Each nucleotide consists of three parts:
Long-term storage of genetic information
Messenger RNA carries genetic code from DNA
Transfer RNA brings amino acids to ribosomes
Ribosomal RNA forms part of ribosomes
Control gene expression and other processes
Correct mutations and damage to genetic material
Nucleic Acids: Store and transfer genetic information using nucleotides (A, T/U, G, C)
Proteins: Perform functions using amino acids (20 types) with diverse structures and activities
Nucleic Acids: Information storage using C, H, O, N, P elements
Carbohydrates: Energy storage and structure using C, H, O in 2:1 ratio
Nucleic Acids: Information molecules with hydrophilic backbone
Lipids: Hydrophobic molecules for energy storage and membrane structure
Watch how complementary strands form the iconic double helix
Observe how nucleotides form complementary pairs
Convert DNA/RNA sequences to amino acid sequences
See how mutations affect protein sequences
Calculate the molecular weight of nucleic acids based on sequence
Analyze the base composition of nucleic acids
Calculate the melting temperature of DNA oligonucleotides
Problem: Given the DNA template strand 5'-ATCGTACGTA-3', what would be the complementary strand sequence?
Solution: The complementary strand would be 3'-TAGCATGCAT-5'. Remember that A pairs with T and G pairs with C. Also note that the complementary strand runs in the opposite direction (antiparallel) to the template strand.
Explanation: Base pairing rules: A=T, G≡C; Antiparallel orientation: 5' to 3' directionality; Hydrogen bonds: 2 between A-T, 3 between G-C
Problem: If the DNA template strand is 3'-TACGTACGTA-5', what would be the resulting mRNA sequence?
Solution: The mRNA sequence would be 5'-AUGC AUGCAU-3'. During transcription, RNA polymerase synthesizes mRNA complementary to the template DNA strand, replacing thymine (T) with uracil (U).
Explanation: Template strand: 3' to 5' direction; mRNA synthesis: 5' to 3' direction; Base pairing: A (DNA) = U (RNA), T (DNA) = A (RNA), G (DNA) ≡ C (RNA), C (DNA) ≡ G (RNA)
Problem: Translate the mRNA sequence 5'-AUGGCCGUAUAU-3' into an amino acid sequence.
Solution: Breaking the sequence into codons: AUG-GCC-GUA-UAU. Amino acid sequence: Met-Ala-Val-Tyr (M-A-V-Y)
Explanation: AUG = Methionine (start codon), GCC = Alanine, GUA = Valine, UAU = Tyrosine
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